8x+3x^2-6x+2x^2+3x+6=180

Solution for 8x+3x^2-6x+2x^2+3x+6=180 equation:

8x+3x^2-6x+2x^2+3x+6=180

We move all terms to the left:

8x+3x^2-6x+2x^2+3x+6-(180)=0

We add all the numbers together, and all the variables

5x^2+5x-174=0

a = 5; b = 5; c = -174;
Δ = b2-4ac
Δ = 52-4·5·(-174)
Δ = 3505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{3505}}{2*5}=\frac{-5-\sqrt{3505}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{3505}}{2*5}=\frac{-5+\sqrt{3505}}{10}
$